The big ideaA cup calorimeter approximates an isolated system: energy lost by hot water should equal energy gained by cold water. Differences reveal heat exchange with the cups, thermometer, air, and timing of the measurements.
The signs tell the story
The lab becomes easier when each water sample is treated as its own system.
Not sure about the basics underneath this lesson?
1
Cold sample
Tf is above Ti, so ΔT and Q are positive. Energy enters.
2
Hot sample
Tf is below Ti, so ΔT and Q are negative. Energy leaves.
3
Compare magnitudes
In the ideal model, the positive and negative amounts cancel. Real lab values differ because the setup is not perfectly isolated.
Should the hot-water Q sign be positive or negative?
Negative, because the hot water loses energy.
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Virtual route: supplied raw data
Trial
Cold water
Hot water
Final temperature
1
250 mL at 20 °C
250 mL at 98 °C
56 °C
2
200 mL at 20 °C
400 mL at 98 °C
72 °C
3
300 mL at 15 °C
150 mL at 90 °C
41 °C
Before you start Review Q = mcΔT from 06.02, including kilograms, joules, and signed temperature change. Open the assigned worksheet and rubric before choosing the manual or virtual route.
Choose one lab route
The manual route uses two Styrofoam cups, a thermometer, a measuring cup, equal 237 mL samples of hot and cold tap water, and careful timing. The virtual route uses the three supplied trials and requires you to build your own clear data table. Download and use the worksheet for the route you select. Do not combine manual measurements with virtual-trial values.
Safety and measurement
Hot tap water can burn. Pour slowly, keep the cup stable, and do not use boiling water. Read the entire procedure before starting. Measure both initial temperatures promptly, mix the water, cover the mixture with the inverted empty cup, and record the stable final temperature while keeping the thermometer bulb in the water.
Lab formulas and units
Water mass
1mL water≈1g=0.001kg
237 mL of water is about 0.237 kg.
Temperature change
ΔT=Tf​−Ti​
Cold water normally has positive ΔT; hot water normally has negative ΔT.
Heat transfer
Q=mcΔT
Use cwater = 4186 J/(kg·K), mass in kg, and Q in J.
Ideal energy balance
Qcold​+Qhot​=0
In a perfectly isolated exchange, magnitudes match.
For the assigned two-water lab, hot water loses energy and cold water gains it as both reach Tf. The nested cups and lid reduce heat loss; remaining mismatch is experimental error.
Manual lab sequence
Prepare
Put 237 mL of cold water in one cup and 237 mL of the hottest safe tap water in the other. Keep the second cup ready to become a lid.
Record initial values
Measure the cold and hot temperatures quickly. Label each value clearly.
Mix and cover
Pour hot into cold, place the thermometer in the mixture, and invert the empty cup over it to reduce exchange with the room.
Find equilibrium
Check about every 20 seconds until the reading stabilizes. Record that as Tf.
Calculate and compare
Convert each 237 mL sample to 0.237 kg, calculate both ΔT values and Q values, then compare |Qhot| with Qcold.
Virtual lab data
Build a table with separate columns for cold volume, cold initial temperature, hot volume, hot initial temperature, final temperature, both masses, both ΔT values, and both Q values. The three trials are supplied below exactly as the course gives them.
Invented calorimetry example
Invented practice data: 180 mL at 18 °C mixed with 220 mL at 78 °C; final 48 °C
Cold mass.mc​=0.180kg
Hot mass.mh​=0.220kg
Cold change.ΔTc​=48−18=30K
Hot change.ΔTh​=48−78=−30K
Compare energy gained by cold water with energy lost by hot water.
Cold-water energy.
Qc​=(0.180)(4186)(30)=2.26×104J
Hot-water energy.
Qh​=(0.220)(4186)(−30)=−2.76×104J
Find the mismatch.
Qc​+Qh​≈−5.02×103J
These invented values are not one of the assigned trials. The water samples alone do not balance perfectly, which can represent energy absorbed by the calorimeter or exchanged with the surroundings plus measurement uncertainty.
Not sure about this bit?
Do the two water samples on separate lines.
1
Copy the shared values
Both use c = 4186 J/(kg·K), but each has its own mass and ΔT.
2
Keep the sign
Do not erase the negative hot-water result. It records direction.
3
Add signed Q values
The remainder estimates energy outside the water-only model plus measurement uncertainty.
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Write the conclusion
Purpose
State that the lab examined thermal-energy transfer and conservation while hot and cold water approached equilibrium.
Finding
Use your own Q values. Say which sample gained energy, which lost energy, and how closely the magnitudes agreed.
Evidence
Include at least one measured temperature and one calculated energy comparison from your chosen route.
Error
Name a mechanism and its likely effect: heat lost to air, energy absorbed by the cup or thermometer, delay in reading temperature, unequal volumes, or thermometer precision.
Not sure about this bit?
Use three short paragraphs if one long paragraph gets tangled.
1
Why
Purpose of mixing the samples.
2
What
Your calculated result and whether energy gains and losses were close.
3
Why not exact
One specific source of error and the direction it would push a measurement.
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Lab-readiness check
These questions check the procedure and analysis without filling in the worksheet for you.