06.04 Thermal Energy Lab

Module 06 — Heat and Particles · quiz worth 30 pts

The big idea A cup calorimeter approximates an isolated system: energy lost by hot water should equal energy gained by cold water. Differences reveal heat exchange with the cups, thermometer, air, and timing of the measurements.

The signs tell the story

The lab becomes easier when each water sample is treated as its own system.

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Virtual route: supplied raw data

TrialCold waterHot waterFinal temperature
1 250 mL at 20 °C 250 mL at 98 °C 56 °C
2 200 mL at 20 °C 400 mL at 98 °C 72 °C
3 300 mL at 15 °C 150 mL at 90 °C 41 °C
Before you start Review Q = mcΔT from 06.02, including kilograms, joules, and signed temperature change. Open the assigned worksheet and rubric before choosing the manual or virtual route.

Choose one lab route

The manual route uses two Styrofoam cups, a thermometer, a measuring cup, equal 237 mL samples of hot and cold tap water, and careful timing. The virtual route uses the three supplied trials and requires you to build your own clear data table. Download and use the worksheet for the route you select. Do not combine manual measurements with virtual-trial values.

Safety and measurement

Hot tap water can burn. Pour slowly, keep the cup stable, and do not use boiling water. Read the entire procedure before starting. Measure both initial temperatures promptly, mix the water, cover the mixture with the inverted empty cup, and record the stable final temperature while keeping the thermometer bulb in the water.

Lab formulas and units

Water mass
1 mL water≈1 g=0.001 kg1\,\text{mL water}\approx1\,\text{g}=0.001\,\text{kg}

237 mL of water is about 0.237 kg.

Temperature change
ΔT=Tf−Ti\Delta T=T_f-T_i

Cold water normally has positive ΔT; hot water normally has negative ΔT.

Heat transfer
Q=mcΔTQ=mc\Delta T

Use cwater = 4186 J/(kg·K), mass in kg, and Q in J.

Ideal energy balance
Qcold+Qhot=0Q_{cold}+Q_{hot}=0

In a perfectly isolated exchange, magnitudes match.

The 06.04 lab mixes equal hot- and cold-water samples, then covers the mixture inside nested Styrofoam cups while a thermometer finds the stable final temperature; the signed balance is Qhot + Qcold = 0 with Qhot negative.
For the assigned two-water lab, hot water loses energy and cold water gains it as both reach Tf. The nested cups and lid reduce heat loss; remaining mismatch is experimental error.

Manual lab sequence

Prepare

Put 237 mL of cold water in one cup and 237 mL of the hottest safe tap water in the other. Keep the second cup ready to become a lid.

Record initial values

Measure the cold and hot temperatures quickly. Label each value clearly.

Mix and cover

Pour hot into cold, place the thermometer in the mixture, and invert the empty cup over it to reduce exchange with the room.

Find equilibrium

Check about every 20 seconds until the reading stabilizes. Record that as Tf.

Calculate and compare

Convert each 237 mL sample to 0.237 kg, calculate both ΔT values and Q values, then compare |Qhot| with Qcold.

Virtual lab data

Build a table with separate columns for cold volume, cold initial temperature, hot volume, hot initial temperature, final temperature, both masses, both ΔT values, and both Q values. The three trials are supplied below exactly as the course gives them.

Invented calorimetry example

Invented practice data: 180 mL at 18 °C mixed with 220 mL at 78 °C; final 48 °C

  • Cold mass. mc=0.180 kgm_c=0.180\,\text{kg}
  • Hot mass. mh=0.220 kgm_h=0.220\,\text{kg}
  • Cold change. ΔTc=48−18=30 K\Delta T_c=48-18=30\,\text{K}
  • Hot change. ΔTh=48−78=−30 K\Delta T_h=48-78=-30\,\text{K}

Compare energy gained by cold water with energy lost by hot water.

  1. Cold-water energy.
    Qc=(0.180)(4186)(30)=2.26×104 JQ_c=(0.180)(4186)(30)=2.26\times10^4\,\text{J}
  2. Hot-water energy.
    Qh=(0.220)(4186)(−30)=−2.76×104 JQ_h=(0.220)(4186)(-30)=-2.76\times10^4\,\text{J}
  3. Find the mismatch.
    Qc+Qh≈−5.02×103 JQ_c+Q_h\approx-5.02\times10^3\,\text{J}

These invented values are not one of the assigned trials. The water samples alone do not balance perfectly, which can represent energy absorbed by the calorimeter or exchanged with the surroundings plus measurement uncertainty.

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Write the conclusion

Purpose

State that the lab examined thermal-energy transfer and conservation while hot and cold water approached equilibrium.

Finding

Use your own Q values. Say which sample gained energy, which lost energy, and how closely the magnitudes agreed.

Evidence

Include at least one measured temperature and one calculated energy comparison from your chosen route.

Error

Name a mechanism and its likely effect: heat lost to air, energy absorbed by the cup or thermometer, delay in reading temperature, unequal volumes, or thermometer precision.

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Lab-readiness check

These questions check the procedure and analysis without filling in the worksheet for you.

Final checklist

Tick these off as you go. Saved in this browser.